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Question: Two closed vessels of an equal volume containing air at pressure \({{P}_{1}}\)​ and temperature \({{...

Two closed vessels of an equal volume containing air at pressure P1{{P}_{1}}​ and temperature T1{{T}_{1}}​ are connected to each other through a narrow tube. If the temperature in one of the vessels is now maintained at T1{{T}_{1}} ​and that in the other at T2{{T}_{2}}​, what will be the pressure in the vessels?
A.​​2P1T1T1+T2\dfrac{2{{P}_{1}}{{T}_{1}}}{{{T}_{1}}+{{T}_{2}}}
B.​​T12P1T2\dfrac{{{T}_{1}}}{2{{P}_{1}}{{T}_{2}}}
C.​​2P1T2T1+T2\dfrac{2{{P}_{1}}{{T}_{2}}}{{{T}_{1}}+{{T}_{2}}}
D.2P1T1+T2\dfrac{2{{P}_{1}}}{{{T}_{1}}+{{T}_{2}}}

Explanation

Solution

Here you need to use the ideal gas equation. This question comes under hard and conceptual type questions. You need to rearrange the ideal gas equation according to the conditions given in the question and the main core concept here is to equate initial and final mole.

Complete step by step answer:
Initial mole = final mole
According to the ideal gas equation:
PV=nRTPV=nRT …………(i)
P1={{P}_{1}}= Initial pressure of both the vessels
T1={{T}_{1}}= Initial temperature of both the vessels
T2={{T}_{2}}= Changed temperature of one vessel
P = Required pressure of vessel

On rearranging equation (i) and then further solving according to question requirement we will get:
n=PVRT P1VT1R+P1VRT1=PVRT1+PVRT2 VR(P1T1+P1T1)=VR(PT1+PT2) 2P1T1=P(1T1+1T2) 2P1T1=P(T2+T1T1T2) 2P1T1T2T1=P(T2+T1) P=2P1T2T1+T2 \begin{aligned} & n=\dfrac{PV}{RT} \\\ & \dfrac{{{P}_{1}}V}{{{T}_{1}}R}+\dfrac{{{P}_{1}}V}{R{{T}_{1}}}=\dfrac{PV}{R{{T}_{1}}}+\dfrac{PV}{R{{T}_{2}}} \\\ & \dfrac{V}{R}\left( \dfrac{{{P}_{1}}}{{{T}_{1}}}+\dfrac{{{P}_{1}}}{{{T}_{1}}} \right)=\dfrac{V}{R}\left( \dfrac{P}{{{T}_{1}}}+\dfrac{P}{{{T}_{2}}} \right) \\\ & \dfrac{2{{P}_{1}}}{{{T}_{1}}}=P\left( \dfrac{1}{{{T}_{1}}}+\dfrac{1}{{{T}_{2}}} \right) \\\ & \dfrac{2{{P}_{1}}}{{{T}_{1}}}=P\left( \dfrac{{{T}_{2}}+{{T}_{1}}}{{{T}_{1}}{{T}_{2}}} \right) \\\ & \dfrac{2{{P}_{1}}{{T}_{1}}{{T}_{2}}}{{{T}_{1}}}=P\left( {{T}_{2}}+{{T}_{1}} \right) \\\ & P=\dfrac{2{{P}_{1}}{{T}_{2}}}{{{T}_{1}}+{{T}_{2}}} \\\ \end{aligned}

So,the correct option is (C).

Note:
The ideal gas law is also called the general gas equation.
The state of a gas is determined by its pressure, temperature and volume according to following equation:
PV=nRTPV=nRT
Here P = pressure
V = volume
R = Universal gas constant
T = temperature
n = number of moles of gas
This ideal gas equation is applicable to gases only not on liquids. Ideal gas is nothing but just a hypothetical concept made by scientists to make calculations and results easier.
An ideal gas can be defined as one in which all collisions between atoms or molecules are perfectly elastic and in which there are no intermolecular attractive forces.