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Question: Two closed organ pipes, when sounded simultaneously gave 4 beats per sec. If longer pipe has a lengt...

Two closed organ pipes, when sounded simultaneously gave 4 beats per sec. If longer pipe has a length of 1m. Then length of shorter pipe will be,

(v = 300 m/s)

A

185.5 cm

B

94.9 cm

C

90 cm

D

80 cm

Answer

94.9 cm

Explanation

Solution

For first pipe n1=v4l1n_{1} = \frac{v}{4l_{1}}and for second pipe n2=v4l2n_{2} = \frac{v}{4l_{2}}

So, number of beats = n2n1=4n_{2} - n_{1} = 4

4=v4(1l21l1)16=300(1l211)\Rightarrow 4 = \frac{v}{4}\left( \frac{1}{l_{2}} - \frac{1}{l_{1}} \right) \Rightarrow 16 = 300\left( \frac{1}{l_{2}} - \frac{1}{1} \right) \Rightarrow l2=94.9cml_{2} = 94.9cm