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Question

Physics Question on Waves

Two closed organ pipes of length 100cm100 \,cm and 101cm101\, cm produces 1616 beats in 20sec.20\, sec . When each pipe is sounded in its fundamental mode calculate the velocity of sound.

A

303ms1303\, ms^{-1}

B

332ms1332\, ms^{-1}

C

323.2ms1323.2\, ms^{-1}

D

300ms1300\, ms^{-1}

Answer

323.2ms1323.2\, ms^{-1}

Explanation

Solution

We get v42v4(1+1)=1620 v4[100100100101]=45 v[1100101]=165 v×1101=165 v=16×1015=323.2m/s\begin{array}{l} \frac{ v }{4^{2}}-\frac{ v }{4(1+1)}=\frac{16}{20} \\\ \Rightarrow \frac{ v }{4}\left[\frac{100}{100}-\frac{100}{101}\right]=\frac{4}{5} \\\ \Rightarrow v \left[1-\frac{100}{101}\right]=\frac{16}{5} \\\ \Rightarrow \frac{ v \times 1}{101}=\frac{16}{5} \\\ \therefore v =\frac{16 \times 101}{5}=323.2 m / s \end{array}