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Question

Physics Question on Moment Of Inertia

Two circular loops of radius RR and nRnR are made from same curve. The moment of inertia about an axis passing through centre and normal to plane of large loop is 88 times that of smaller loop. The value of nn is

A

3

B

4

C

2

D

1

Answer

2

Explanation

Solution

Given that, Mass of one 100p=M100 p=M Mass of nn coop =nM=n M Radius of one 100p=R100 p=R Radius of nn loop =nR=n R Now, moment of Inertia, ImInm=18 mR2nM×nR2=18 1n3=18 n3=8 n=2\begin{array}{c} \frac{I_{m}}{I_{n m}}=\frac{1}{8} \\\ \frac{m R^{2}}{n M \times n R^{2}}=\frac{1}{8} \\\ \frac{1}{n^{3}}=\frac{1}{8} \\\ n^{3}=8 \\\ n=2 \end{array}