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Question: Two circuits have coefficient of mutual induction of 0.09 henry. Average e.m.f. induced in the secon...

Two circuits have coefficient of mutual induction of 0.09 henry. Average e.m.f. induced in the secondary by a change of current from 0 to 20 ampere in 0.006 second in the primary will be

A

120 V

B

80 V

C

200 V

D

300 V

Answer

300 V

Explanation

Solution

e=Mdidt=0.09×200.006=3006muVe = M\frac{di}{dt} = 0.09 \times \frac{20}{0.006} = 300\mspace{6mu} V