Question
Question: Two circles touch internally. The sum of their areas is \[170\pi c{m^2}\] and the distance between t...
Two circles touch internally. The sum of their areas is 170πcm2 and the distance between their centres is 4cm. Find the radii of the circles.
A. 13cm,5cm
B. 12cm,8cm
C. 13cm,9cm
D. 11cm,7cm
Solution
Hint: Consider two variables as the radii of the two circles. The distance between their radii is equal to the difference of the radii of the two circles. The area of the circle with radius rcm is given by πr2cm2. So, use this concept to reach the solution of the problem.
Complete step-by-step answer:
Let R be the radius of circle A and r be the radius of circle B.
Given distance between their centres is 4cm i.e., R−r=4cm..................(1)
Area of the circle A = πR2cm2
Area of the circle B = πr2cm2
Since, the sum of the areas of the circles is 170πcm2, we have πR2+πr2=170π.................(2)
From (1) we have R=4+r
Substituting the value of R in equation (2), we get
\Rightarrow \pi {\left( {4 + r} \right)^2} + \pi {r^2} = 170\pi \\\ \Rightarrow \pi \left\\{ {{{\left( {4 + r} \right)}^2} + {r^2}} \right\\} = 170\pi \\\ \Rightarrow \left( {16 + {r^2} + 8r} \right) + {r^2} = 170 \\\ \Rightarrow 16 + {r^2} + 8r + {r^2} = 170 \\\ \Rightarrow 2{r^2} + 8r - 154 = 0 \\\Splitting the terms, we have
⇒2r2+22r−14r−154=0 ⇒2r(r+11)−14(r+11)=0 ⇒(2r−14)(r+11)=0 ⇒r=7,−11 ∴r=7cmFrom equation (1), we have
⇒R−7=4 ⇒R=7+4=11 ∴R=11cmTherefore, the radius of the circles is 11cm and 7cm.
Thus, the correct option is D, 11cm,7cm
Note: Here we neglected the negative value of radius as radius cannot be negative. In the given question we can easily say that the radius of circle A is greater than the radius of circle B by the given diagram. Don’t forget to write the units after the areas of the circles and radii of the circle i.e., c{m^2}{\text{ & }}cm respectively.