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Question

Physics Question on potential energy

Two charges of magnitude 5nC5\, nC and 2nC-2\, nC, one placed at points (2cm,0,0)(2\, cm, 0,\, 0) and (xcm,0,0)(x \,cm, 0, 0) in a region of space, where there is no other external field. If the electrostatic potential energy of the system is 0.5μJ-0.5 \, \mu J. The value of xx is

A

20cm20\, cm

B

80cm80\, cm

C

4cm4\, cm

D

16cm16\, cm

Answer

20cm20\, cm

Explanation

Solution

Potential energy of system U=14πε0q1q2rU=\frac{1}{4\pi\varepsilon_{0}} \frac{q_{1}q_{2}}{r} 0.5×106=9×109×5×109×(2)×109(x2)×1020.5\times10^{-6}=\frac{9\times10^{9}\times5\times10^{-9}\times\left(-2\right)\times10^{-9}}{\left(x-2\right)\times10^{-2}} x=20cm\Rightarrow x=20 \, cm