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Question: Two charges of magnitude 5 nC and \(- 2nC,\) one placed at points (2 cm, 0,0) and (x cm, 0,0) in a r...

Two charges of magnitude 5 nC and −2nC,- 2nC, one placed at points (2 cm, 0,0) and (x cm, 0,0) in a region of space, where there is no other external field. If the electrostatic potential energy of the system is −0.5μJ.- 0.5\mu J. The value of x is.

A

20 cm

B

80 cm

C

4 cm

D

16 cm

Answer

20 cm

Explanation

Solution

: Potential energy of system

U=14πε0q1q2rU = \frac{1}{4\pi\varepsilon_{0}}\frac{q_{1}q_{2}}{r}

0.5×10−6=9×109×5×10−9×(−2)×10−9(x−2)×10−20.5 \times 10^{- 6} = \frac{9 \times 10^{9} \times 5 \times 10^{- 9} \times ( - 2) \times 10^{- 9}}{(x - 2) \times 10^{- 2}}

⇒x=20cm.\Rightarrow x = 20cm.