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Question: Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges ar...

Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is

A

F / 8

B

F / 4

C

4 F

D

F / 16

Answer

F / 16

Explanation

Solution

F=k.Q2r2F = k.\frac{Q^{2}}{r^{2}}. If Q is halved, r is doubled then

F→116timesF \rightarrow \frac{1}{16}\text{times}