Question

Two charges equal in magnitude and opposite in polarity are placed at a certain distance apart and force acting between them is F. If 75% charge of one is transferred to another, then the force between the charges becomes

• A. $\frac{F}{16}$
• B. $\frac{9F}{16}$
• C. $F$
• D. $\frac{15}{16}F$

Answer 1

Answer: (A)

$\frac{F}{16}$

Answer 2

Initially $F = k\frac{Q^{2}}{r^{2}}$

Finally $F' = \frac{k.\left( \frac{Q}{4} \right)^{2}}{r^{2}} = \frac{F}{16}$