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Question: Two charges each of \(1\mspace{6mu} coulomb\)are at a distance \(1km\) apart, the force between them...

Two charges each of 16mucoulomb1\mspace{6mu} coulombare at a distance 1km1km apart, the force between them is

A

9×1036muNewton9 \times 10^{3}\mspace{6mu} Newton

B

9×1036muNewton9 \times 10^{- 3}\mspace{6mu} Newton

C

1.1×1046muNewton1.1 \times 10^{- 4}\mspace{6mu} Newton

D

1046muNewton10^{4}\mspace{6mu} Newton

Answer

9×1036muNewton9 \times 10^{3}\mspace{6mu} Newton

Explanation

Solution

F=kQ2r2=9×109×12×1(1000)2=9×103NF = \frac{kQ^{2}}{r^{2}} = 9 \times 10^{9} \times 1^{2} \times \frac{1}{(1000)^{2}} = 9 \times 10^{3}N