Question

Two charges each equal to $2\mu C$ are 0.5m apart. If both of them exist inside vacuum, then the force between them is

• A. 1.89 N
• B. 2.44 N
• C. 0.144 N
• D. 3.144 N

Answer 1

Answer: (C)

0.144 N

Answer 2

By using $F = 9 \times 10^{9}.\frac{Q^{2}}{r^{2}}$

⇒ $F = 9 \times 10^{9}.\frac{(2 \times 10^{- 6})^{2}}{(0.5)^{2}} = 0.144N$