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Question

Physics Question on Electric charges and fields

Two charged spherical conductors of radii R1{{R}_{1}} and R2{{R}_{2}} are connected by a wire. Then the ratio of surface charge densities of the spheres σ1/σ2{{\sigma }_{1}}/{{\sigma }_{2}} is

A

R1/R2{{R}_{1}}/{{R}_{2}}

B

R2/R1{{R}_{2}}/{{R}_{1}}

C

(R1/R2)\sqrt{({{R}_{1}}/{{R}_{2}})}

D

R12/R22R_{1}^{2}/R_{2}^{2}

Answer

R2/R1{{R}_{2}}/{{R}_{1}}

Explanation

Solution

q1q2=C1C2=R1R2\frac{{{q}_{1}}}{{{q}_{2}}}=\frac{{{C}_{1}}}{{{C}_{2}}}=\frac{{{R}_{1}}}{{{R}_{2}}} and q1q2=4πR12σ14πR22σ2\frac{{{q}_{1}}}{{{q}_{2}}}=\frac{4\pi R_{1}^{2}{{\sigma }_{1}}}{4\pi R_{2}^{2}{{\sigma }_{2}}} R1R2=4πR12σ14πR22σ2\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{4\pi R_{1}^{2}{{\sigma }_{1}}}{4\pi R_{2}^{2}{{\sigma }_{2}}} \therefore σ1σ2=R2R1\frac{{{\sigma }_{1}}}{{{\sigma }_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}