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Question

Physics Question on Electrostatics

Two charged conducting spheres of radii a and b are connected to each other by a conducting wire. The ratio of charges of the two spheres respectively is:

A

ab\sqrt{ab}

B

ab

C

ab\frac{a}{b}

D

ba\frac{b}{a}

Answer

ab\frac{a}{b}

Explanation

Solution

The potential at the surface of a conducting sphere is given by:

V=KqrV = \frac{Kq}{r}.

Since the two spheres are connected, their potentials will be the same:

Kq1a=Kq2b.\frac{Kq_1}{a} = \frac{Kq_2}{b}.

Simplifying:

q1q2=ab.\frac{q_1}{q_2} = \frac{a}{b}.

Final Answer: ab\frac{a}{b}.