st","extracted_subject":"PHYSICS","extracted_chapter":"CURRENT ELECTRICITY","extracted_topic":"CELLS, EMF, INTERNAL RESISTANCE","questionPreviewUrl":"https://cdn.pureessence.tech/question-previews/packed_canvases/canvas_590.png?top_left_x=1064&top_left_y=971&width=532&height=334&app=solveeit"},"seo_metadata":{"keywords":[]},"doubt_solver_data":{"concept_summary":[]},"embeddings":[],"is_hidden":false,"_id":"66d23c8270136192204bdaa5","slug":"two-cells-of-emf-esub1sub-and-esub2sub-esub2sub-es","content":"Two cells of emf E₁ and E₂ (E₂\\> E₁) are connected in series in a secondary circuit of a potentiometer experiment for determination of emf. The balancing length is found to be 825 cm. Now when the terminals of cell of emf E₁ are reversed, then the balancing length is found to be 225 cm. The ratio of E₁ and E₂ is, then-","options":[{"_id":"68a397ef7f15af4716badfcf","text":"2 : 3","sequence":0,"isCorrect":false},{"_id":"68a397ef7f15af4716badfd0","text":"4 : 7","sequence":1,"isCorrect":true},{"_id":"68a397ef7f15af4716badfd1","text":"7 : 4","sequence":2,"isCorrect":false},{"_id":"68a397ef7f15af4716badfd2","text":"None of these","sequence":3,"isCorrect":false}],"correct_answer":"4 : 7","explanation":"E₂ + E₁ = x(825)\n\nE₂ – E₁ = x (225)","question_type":"single_choice","appeared_in":[],"created_at":"2024-08-30T21:41:22.618Z","__v":0,"vector_store_id":"704e9bd7-a22f-420d-9980-f4c7e5fe8dd4","updated_at":"2024-08-30T21:41:22.618Z","isStarred":false},"params":{"questionSlug":"two-cells-of-emf-esub1sub-and-esub2sub-esub2sub-es"}}]}]]

Question: Two cells of emf E<sub>1</sub> and E<sub>2</sub> (E<sub>2</sub>\> E<sub>1</sub>) are connected in se...

Solution