Solveeit Logo

Question

Physics Question on Motion in a straight line

Two cars started moving with initial velocities vv and 2v2v. For the same deceleration, their respective stopping distances are in the ratio

A

1:01

B

1:02

C

1:04

D

2:01

Answer

1:04

Explanation

Solution

For first car v12=u22asv_{1}^{2} =u^{2}-2 a s 0=v2as10 =v-2 a s_{1} s1=v2as_{1} =\frac{v}{2 a} For second car v22=u22as v_{2}^{2}=u^{2}-2 a s 0=(2v)22as20=(2 v)^{2}-2 a s_{2} s2=2vas_{2}=\frac{2 v}{a} s1s2=v2a2va\therefore \frac{s_{1}}{s_{2}} =\frac{\frac{v}{2 a}}{\frac{2 v}{a}} s1s2=14\therefore \frac{s_{1}}{s_{2}} =\frac{1}{4}