Question
Physics Question on Motion in a straight line
Two cars started moving with initial velocities v and 2v. For the same deceleration, their respective stopping distances are in the ratio
A
1:01
B
1:02
C
1:04
D
2:01
Answer
1:04
Explanation
Solution
For first car v12=u2−2as 0=v−2as1 s1=2av For second car v22=u2−2as 0=(2v)2−2as2 s2=a2v ∴s2s1=a2v2av ∴s2s1=41