Question
Question: Two cars start off to race with velocities \( 4m/s \) and \( 2m/s \) and travel in a straight line w...
Two cars start off to race with velocities 4m/s and 2m/s and travel in a straight line with uniform acceleration 1m/s2 and 2m/s2 respectively. If they reach the final point at the same time, then the length of the path is
A) 24m
B) 30m
C) 12m
D) 45m
Solution
In this solution, we will calculate the distance travelled by the two cars given with their initial velocities and acceleration. Since they reach the final point at the same time, they will cover the same amount of distance in equal amounts of time.
Formula used In this solution, we will use the following formula:
-Second equation of kinematics: d=ut+21at2 where d is the distance covered by an object travelling with an initial velocity u , constant acceleration a in time t
Complete step by step answer:
We’ve been given that two cars start off to race with different velocities and different acceleration and they reach the finish line at the same time.
For the first car, we have u1=4m/s and a1=1m/s2 , so we can use the second equation of kinematics and write
d=4t+21(1)t2
For the first car, we have u2=2m/s and a2=2m/s2 , so we can again use the second equation of kinematics. Since both the cars cross the finish point at the same point, they will cover an equal distance d in time t , so we can write
d=2t+21(2)t2
⇒d=2t+t2
Comparing equation (1) and (2), we can write
4t+2t2=2t+t2
Which can be simplified to
t2−4t=0
Or
t(t−4)=0
Hence t=0 or t=4 seconds. Since t=0 is arbitrary, the time taken by the cars to cross the finish point will be t=4s . The distance the first car will cover at this time will be
d=4(4)+21(1)(4)2
⇒d=24m
Hence option (A) will be the correct choice.
Note:
The distance travelled by both the cars will be the same so we can only calculate the distance travelled by one of the cars to find the answer. This scenario is only possible when the car with the greater initial velocity has a smaller acceleration than the second car.