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Question

Physics Question on physical world

Two cars are in a race. The white car passed the finishing point with a velocity vms1v\, ms^{-1} more and took time tst\, s less than the red car. If both the cars start from rest and travel with constant accelerations awa_w , and ara_r respectively, vt\frac{v}{t} is given

A

awara_w\, a_r

B

awar\sqrt{\frac{a_{w}}{a_{r}}}

C

awar\sqrt{a_{w}\, a_{r}}

D

araw\sqrt{\frac{a_{r}}{a_{w}}}

Answer

awar\sqrt{a_{w}\, a_{r}}

Explanation

Solution

We have, v=u+atv = u + at
For White car, v=awtv = a_w t
vt=aw[u=0]...(i)\Rightarrow \frac{v}{t} = a_w \,\,\,\,\,\,[u = 0 ] ...(i)
For red car, vR=artrvrtr=ar...(ii)v_R = a_r t_r \,\,\frac{v_r}{t_r} = a_r \,\,\,\,\,...(ii)
So, vtvrtr=awar\frac{v}{t} \cdot \frac{v_r}{t_r} = a_w \cdot a_r
Suppose vvRv \approx v_R and ttr t \approx t_r
v2t2=awar\frac{v^2}{t^2} = a_w \cdot a_r
vt=awar\frac{v}{t} = \sqrt{a_w \cdot a_r}