Question

Two cards are drawn without replacement. The probability distribution of number of aces is given by:

• A.

  X	0	1	2
  P(X)	$\frac{188}{221}$	$\frac{32}{221}$	$\frac{1}{221}$

• B.

  X	0	1	2
  P(X)	$\frac{144}{169}$	$\frac{24}{169}$	$\frac{1}{169}$

• C.

  X	0	1	2
  P(X)	$\frac{188}{221}$	$\frac{24}{221}$	$\frac{1}{221}$

• D.

  X	0	1	2
  P(X)	$\frac{188}{221}$	$\frac{1}{221}$	$\frac{24}{221}$

Answer 1

Answer: (A)

X	0	1	2
P(X)	$\frac{188}{221}$	$\frac{32}{221}$	$\frac{1}{221}$

Answer 2

The correct option is (A): X	0	1	2
P(X)	$\frac{188}{221}$	$\frac{32}{221}$	$\frac{1}{221}$