Question

Two cards are drawn one by one from a pack of cards. The

probability of getting first card an ace and second an honour card is (before drawing second card first card is not placed again in the pack)

• A. 1/26
• B. 5/52
• C. 5/221
• D. 4/13

Answer 1

Answer: (C)

5/221

Answer 2

$= \mathrm { P } ( \mathrm { A } \cap \mathrm { B } ) \cup \mathrm { P } ( \overline { \mathrm { A } } \cap \mathrm { B } )$

$P \left( E _ { 1 } \cap E _ { 2 } \right) = P \left( E _ { 1 } \right) \cdot P \left( \frac { E _ { 2 } } { E _ { 1 } } \right) = \frac { 1 } { 13 } \cdot \frac { 5 } { 17 } = \frac { 5 } { 221 }$.