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Question

Question: Two cards are drawn from a pack of \(52\) cards. Find the probability distribution of (i) \(X=\) n...

Two cards are drawn from a pack of 5252 cards. Find the probability distribution of
(i) X=X= number of picture cards
(ii) Y=Y= number of black cards
(iii) Z=Z= number of diamond cards.

Explanation

Solution

In this problem we have to calculate the probability distribution of the given cards. In the question they have mentioned that two cards are drawn from a pack of 5252, so we will take the number of ways to draw two cards from 5252 cards. For each case we will write the number of cards we have and the number ways to draw two cards. Now we will take the ratio of both the values, to get the required probability.

Complete Step by Step Solution:
Given that, two cards are drawn from the pack of 5252 cards.
We can take two cards from 5252 cards in 52C2{}^{52}{{C}_{2}} ways.
Considering the first case.
In this case they have mentioned picture cards.
In a pack of 5252 we have 1212 picture cards.
We can take two cards from 1212 picture cards in 12C2{}^{12}{{C}_{2}}.
Now the probability of the first case is
P(X)=12C252C2P\left( X \right)=\dfrac{{}^{12}{{C}_{2}}}{{}^{52}{{C}_{2}}}
Considering the second case.
In this case they have mentioned about black cards.
In a pack of 5252 we have 2626 black cards.
We can take two cards from 2626 picture cards in 26C2{}^{26}{{C}_{2}}.
Now the probability of the first case is
P(Y)=26C252C2P\left( Y \right)=\dfrac{{}^{26}{{C}_{2}}}{{}^{52}{{C}_{2}}}.
Considering the third case.
In this case they have mentioned diamond cards.
In a pack of 5252 we have 1313 black cards.
We can take two cards from 1313 picture cards in 13C2{}^{13}{{C}_{2}}.
Now the probability of the first case is
P(Y)=13C252C2P\left( Y \right)=\dfrac{{}^{13}{{C}_{2}}}{{}^{52}{{C}_{2}}}.

Note:
For the problems related to playing cards, we need to have some clarity about the number of different cards in the pack. The typical pack is given by