Question

Two capacitors of $2\mu F$ and $4\mu F$are connected in parallel. A third capacitor of $6\mu F$ is connected in series. The combination is connected across 12 V battery. The voltage across $2\mu V$ capacitor is

• A. 2 V
• B. 8 V
• C. 6 V
• D. 1 V

Answer 1

Answer: (C)

6 V

Answer 2

:

$C_{P} = 2 + 4 = 6\mu F$

$\frac{1}{C} = \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3}$ or $C = 3\mu F$

Total charge, $Q = CV = 3 \times 12 = 36\mu C$

Voltage across $6\mu F$capacitor $= \frac{36\mu C}{6\mu F} = 6V$

$\therefore$Voltage across each of $2\mu F$ and $4\mu F$ capacitors

}{V = 6V}$$