Solveeit Logo

Question

Question: Two capacitors each of \(1 \mu F\) capacitance are connected in parallel and are then charged by 20...

Two capacitors each of 1μF1 \mu F capacitance are connected in parallel and are then charged by 200 volts d.c. supply. The total energy of their charges (in joules) is

A

0.01

B

0.02

C

0.04

D

0.06

Answer

0.04

Explanation

Solution

U=12CV2=12×2×(200)2×106=0.04JU = \frac { 1 } { 2 } C V ^ { 2 } = \frac { 1 } { 2 } \times 2 \times ( 200 ) ^ { 2 } \times 10 ^ { - 6 } = 0.04 J