Question

Two capacitors each of 1 μ f capacitance are connected in parallel and are then charged by 200 V D.C. supply. The total energy of their charges in joules is

• A. 0.01
• B. 0.02
• C. 0.04
• D. 0.06

Answer 1

Answer: (C)

0.04

Answer 2

By using formula $U = \frac{1}{2}C_{eq}V^{2}$

Here $C_{eq} = 2\mu F$

∴ $U = \frac{1}{2} \times 2 \times 10^{- 6} \times (200)^{2} = 0.04J$