Question
Question: Two capacitors C<sub>1</sub> = 2μF and C<sub>2</sub> = 6μF in series, are connected in parallel to a...
Two capacitors C1 = 2μF and C2 = 6μF in series, are connected in parallel to a third capacitor C3 = 4μF. This arrangement is then connected to a battery of e.m.f. = 2 V, as shown in the fig. How much energy is lost by the battery in charging the capacitors ?

A
22×10−6J
B
11×10−6J
C
D
(316)×10−6J
Answer
11×10−6J
Explanation
Solution
Equivalent capacitance
Ceq=C1+C2C1C2+C3=82×6+4=5.5μF∴