Question

Two capacitances of capacity $C_{1}$and $C_{2}$ are connected in series and potential difference $V$ is applied across it. Then the potential difference across $C_{1}$will be

• A. $V\frac{C_{2}}{C_{1}}$
• B. $V\frac{C_{1} + C_{2}}{C_{1}}$
• C. $V\frac{C_{2}}{C_{1} + C_{2}}$
• D. $V\frac{C_{1}}{C_{1} + C_{2}}$

Answer 1

Answer: (C)

$V\frac{C_{2}}{C_{1} + C_{2}}$

Answer 2

Charge flowing $= \frac{C_{1}C_{2}}{C_{1} + C_{2}}V$. So potential difference across $C_{1} = \frac{C_{1}C_{2}V}{C_{1} + C_{2}} \times \frac{1}{C_{1}} = \frac{C_{2}V}{C_{1} + C_{2}}$