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Question: Two bulbs of 500 watt and 200 watt are manufactured to operate on 220 volt line. The ratio of heat p...

Two bulbs of 500 watt and 200 watt are manufactured to operate on 220 volt line. The ratio of heat produced in 500 W and 200 W, in two cases, when firstly they are joined in parallel and secondly in series, will be

A

52,25\frac{5}{2},\frac{2}{5}

B

52,52\frac{5}{2},\frac{5}{2}

C

25,52\frac{2}{5},\frac{5}{2}

D

25,25\frac{2}{5},\frac{2}{5}

Answer

52,25\frac{5}{2},\frac{2}{5}

Explanation

Solution

Resistance R1R_{1} of 500 W bulb =(220)2500= \frac{(220)^{2}}{500}

Resistance R2R_{2} of 200 W bulb =(220)2200= \frac{(220)^{2}}{200}

When joined in parallel, the potential difference across both the bulbs will be same.

Ratio of heat produced =V2/R1V2/R2=R2R1=52= \frac{V^{2}/R_{1}}{V^{2}/R_{2}} = \frac{R_{2}}{R_{1}} = \frac{5}{2}

When joined in series, the same current will flow through both the bulbs.

Ratio of heat produced =i2R1i2R2=R1R2=25= \frac{i^{2}R_{1}}{i^{2}R_{2}} = \frac{R_{1}}{R_{2}} = \frac{2}{5}