Question

Two bulbs are in parallel and they together consume 48 W from a battery of 6 V. The resistance of each bulb is

• A. $0.67\Omega$
• B. $3.0\Omega$
• C. $4.0\Omega$
• D. $1.5\Omega$

Answer 1

Answer: (D)

$1.5\Omega$

Answer 2

The bulbs are connected in parallel, hence each bulb consumes $\frac{48}{2} = 24W.$ Therefore $\frac{V^{2}}{R} = 24$

⇒ $R = \frac{6 \times 6}{24} = 1.5\Omega$