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Question

Physics Question on Kinetic Energy

Two bodies with kinetic energies in the ratio 4:14 : 1 are moving with same linear momenta. The ratio of their masses is

A

1:04

B

1:01

C

1:02

D

4:01

Answer

1:04

Explanation

Solution

K.E. = p22m\frac{p^2}{2m} Here K.E. ∝1m    ∴   K.E.2K.E.1=m1m2=14\propto \frac{1}{m} \:\:\:\: \therefore \:\:\:\frac{K.E._2}{K.E._1} = \frac{m_1}{m_2} = \frac{1}{4}