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Question

Physics Question on work, energy and power

Two bodies of masses m and 4m are moving with equal kinetic energies. The ratio of their linear momenta is

A

1:21 : 2

B

1:41 : 4

C

4:14 : 1

D

1:11 : 1

Answer

1:21 : 2

Explanation

Solution

Mass of first body = m;

Mass of second body = 4m and KE1_1 = KE2_2.

Linear momentum of a body

p=2mEm.\sqrt{2mE} \sqrt m .

Therefore p1p2=m1m2=m4m=14=12\frac{p_1}{p_2}=\sqrt{\frac{m_1}{m_2}}=\sqrt{\frac{m}{4m}}=\sqrt{\frac{1}{4}}=\frac{1}{2}

or p1:p2=1:2.p_1:p_2 = 1: 2.