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Question: Two bodies of masses \({m_1}\) and \({m_2}\) are acted upon by a constant force \(F\) for a time \(t...

Two bodies of masses m1{m_1} and m2{m_2} are acted upon by a constant force FF for a time tt. They start from rest and acquire kinetic energies E1{E_1} and E2{E_2} respectively. Then E1E2\dfrac{{{E_1}}}{{{E_2}}} is:
A. m1m2\dfrac{{{m_1}}}{{{m_2}}}
B. m2m1\dfrac{{{m_2}}}{{{m_1}}}
C. 11
D. m1m2m1+m2\dfrac{{\sqrt {{m_1}{m_2}} }}{{{m_1} + {m_2}}}

Explanation

Solution

Kinetic energy is generally possessed due to the motion of the object; it is the amount of work needed to be done no that body to accelerate it for achieving the stable velocity from rest.To solve this we will make use of the formula of kinetic energy.

Complete step by step solution:
Given that,
The mass of the bodies are m1{m_1} and m2{m_2} on which force FF is applied for timet.
The acceleration generated due to that force on body m1=Fm1{m_1} = \dfrac{F}{{{m_1}}}
The acceleration generated due to that force on body m2=Fm2{m_2} = \dfrac{F}{{{m_2}}}
As we know, velocity will be equal to product of acceleration and time;
Velocity = Acceleration ×\times time
Let, the velocities acquired by bodies m1{m_1} and m2{m_2}
For mass m1{m_1} velocity is v1=Fm1×t{v_1} = \dfrac{F}{{{m_1}}} \times t
For mass m2{m_2} velocity is v2=Fm2×t{v_2} = \dfrac{F}{{{m_2}}} \times t
As we know that, Kinetic energy E=12×m×v2E = \dfrac{1}{2} \times m \times {v^2}
Let, the kinetic energies acquired by bodies m1{m_1}and m2{m_2}be E1{E_1} andE2{E_2};
So, the ratio between E1{E_1} and E2{E_2} is
E1E2=12×m1×v1212×m2×v22\dfrac{{{E_1}}}{{{E_2}}} = \dfrac{{\dfrac{1}{2} \times {m_1} \times {v_1}^2}}{{\dfrac{1}{2} \times {m_2} \times {v_2}^2}}
E1E2=12×m1×(Fm1×t)212×m2×(Fm2×t)2\dfrac{{{E_1}}}{{{E_2}}} = \dfrac{{\dfrac{1}{2} \times {m_1} \times {{\left( {\dfrac{F}{{{m_1}}} \times t} \right)}^2}}}{{\dfrac{1}{2} \times {m_2} \times {{\left( {\dfrac{F}{{{m_2}}} \times t} \right)}^2}}}
On solving we get
E1E2=m2m1\dfrac{{{E_1}}}{{{E_2}}} = \dfrac{{{m_2}}}{{{m_1}}}
Hence, the correct option is B.

Note: The kinetic energy is a form of energy which arises within the body by the application of some force or work on it. It is proportional to the velocity of the moving body. It also depends on the mass of the moving objects.