Question
Question: Two bodies of masses \({m_1}\) and \({m_2}\) are acted upon by a constant force \(F\) for a time \(t...
Two bodies of masses m1 and m2 are acted upon by a constant force F for a time t. They start from rest and acquire kinetic energies E1 and E2 respectively. Then E2E1 is:
A. m2m1
B. m1m2
C. 1
D. m1+m2m1m2
Solution
Kinetic energy is generally possessed due to the motion of the object; it is the amount of work needed to be done no that body to accelerate it for achieving the stable velocity from rest.To solve this we will make use of the formula of kinetic energy.
Complete step by step solution:
Given that,
The mass of the bodies are m1 and m2 on which force F is applied for timet.
The acceleration generated due to that force on body m1=m1F
The acceleration generated due to that force on body m2=m2F
As we know, velocity will be equal to product of acceleration and time;
Velocity = Acceleration × time
Let, the velocities acquired by bodies m1 and m2
For mass m1 velocity is v1=m1F×t
For mass m2 velocity is v2=m2F×t
As we know that, Kinetic energy E=21×m×v2
Let, the kinetic energies acquired by bodies m1and m2be E1 andE2;
So, the ratio between E1 and E2 is
E2E1=21×m2×v2221×m1×v12
E2E1=21×m2×(m2F×t)221×m1×(m1F×t)2
On solving we get
E2E1=m1m2
Hence, the correct option is B.
Note: The kinetic energy is a form of energy which arises within the body by the application of some force or work on it. It is proportional to the velocity of the moving body. It also depends on the mass of the moving objects.