Question

Two bodies of masses 8 kg are placed at the vertices A and B of an equilateral triangle ABC. A third body of mas 2 kg is placed at the centroid G of the triangle. If AG = BG = CG = 1 m, where should a fourth body of mass 4 kg be placed so that the resultant force on the 2 kg body is zero?

• A. At C
• B. At a point on the line CG such that PG = $\frac{1}{\sqrt2}$m
• C. At a point P on the line CG such that PG=0.5 m
• D. At a point P on the line CG such that PG=2m

Answer 1

Answer: (B)

At a point on the line CG such that PG = $\frac{1}{\sqrt2}$m

Answer 2

The correct answer is (B) : At a point on the line CG such that PG = $\frac{1}{\sqrt2}$m