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Question: Two bodies of equal masses are placed at heights h and 2h. The ratio of their gravitational potentia...

Two bodies of equal masses are placed at heights h and 2h. The ratio of their gravitational potential energies is:
A. 1
B. 2
C. 12\dfrac{1}{2}
D. 14\dfrac{1}{4}

Explanation

Solution

Hint: U=mghU=mgh is the relation of gravitational potential energy and the height at which the object is placed.

Complete step by step answer:
The formula of potential energy is;
U=mghU=mgh, where m is the object, g is the acceleration due to gravity and h is the height at which the object is placed.
Consider two objects of the same mass and places at different heights.
So h1{{h}_{1}} is the height at which the first body is placed and h2{{h}_{2}} is the height at which the second body placed.
From this date we can find the potential energy of each body.
Potential energy of first body, U1=mgh1{{U}_{1}}=mg{{h}_{1}}
Potential energy of second body, U2=mgh2{{U}_{2}}=mg{{h}_{2}}
Ratio of the potential energy of these two objects will be, U1U2=mgh1mgh2\dfrac{{{U}_{1}}}{{{U}_{2}}}=\dfrac{mg{{h}_{1}}}{mg{{h}_{2}}}
Here, m and g are constant for two bodies. Thus, U1U2=h1h2\dfrac{{{U}_{1}}}{{{U}_{2}}}=\dfrac{{{h}_{1}}}{{{h}_{2}}}
We can assign values to the heights,
As per the given data, h1=h{{h}_{1}}=h and h2=2h{{h}_{2}}=2h.
U1U2=h2h\dfrac{{{U}_{1}}}{{{U}_{2}}}=\dfrac{h}{2h}
U1U2=12\dfrac{{{U}_{1}}}{{{U}_{2}}}=\dfrac{1}{2}
Hence the ratio of potential energy is 1:21:2. Therefore, the option C is correct.

Additional information:
Potential energy is a form of energy by the virtue of the shape or position of the body. Stretched bows, stretched rubber bands are coming under the potential energy. Similarly, an object placed at a height has the potential energy to do work. For this energy gravity of earth is also responsible. It is actually formulated from Newton’s second law of motion.
Workdone = force × displacement\text{Workdone = force }\times \text{ displacement}
Force = mass !!×!! acceleration\text{Force = mass }\\!\\!\times\\!\\!\text{ acceleration}
F=mgF=mg, where g is the acceleration due to gravity.
Displacement = h
Therefore, Workdone = mgh\text{Workdone = mgh}
This work done is actually the energy gained by the object and it is known as gravitational potential energy.

Note: The potential energy will increase with the increase of height, since direct relationship of height and potential energy.