Question

Two bodies of different masses $m_a \, and \, m_b$ are allowed to fall from different heights $a$ and $b$. The ratio of time taken by the two to cover these distances are

• A. a : b
• B. b : a
• C. $\sqrt a:\sqrt b$
• D. $a^2 :b^2$.

Answer 1

Answer: (C)

$\sqrt a:\sqrt b$

Answer 2

Using, S = $ut + \frac{1}{2} gt^2$, we get $t \propto \sqrt{s}$ $\therefore t_2:t_2::\sqrt{a}:\sqrt{b}$