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Question

Question: Two bodies of different masses \(m _ { 1 }\) and \(m _ { 2 }\) have equal momenta. Their kinetic ene...

Two bodies of different masses m1m _ { 1 } and m2m _ { 2 } have equal momenta. Their kinetic energies E1E _ { 1 } and E2E _ { 2 } are in the ratio

A

m1:m2\sqrt { m _ { 1 } } : \sqrt { m _ { 2 } }

B

m1:m2m _ { 1 } : m _ { 2 }

C

m2:m1m _ { 2 } : m _ { 1 }

D

m12:m22m _ { 1 } ^ { 2 } : m _ { 2 } ^ { 2 }

Answer

m2:m1m _ { 2 } : m _ { 1 }

Explanation

Solution

E=P22mE = \frac { P ^ { 2 } } { 2 m } if bodies possess equal linear momenta then

E1mE \propto \frac { 1 } { m } i.e. E1E2=m2m1\frac { E _ { 1 } } { E _ { 2 } } = \frac { m _ { 2 } } { m _ { 1 } }