Solveeit Logo

Question

Physics Question on Motion in a straight line

Two bodies begin to fall freely from the same height. The second one begins to fall τ\tau s after the first. The time after which the 1st body begins to fall, the distance between the bodies equals to ll is

A

lgτ+τ2\frac{l}{g\tau}+\frac{\tau}{2}

B

gτl+τ\frac{g\tau}{l}+{\tau}

C

τlg+2τ\frac{\tau}{l \,g}+\frac{2}{\tau}

D

glτ+τ2\frac{g}{l\,\tau}+\frac{\tau}{2}

Answer

lgτ+τ2\frac{l}{g\tau}+\frac{\tau}{2}

Explanation

Solution

S=ut+12at2S = ut + \frac{1}{2} at^2