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Question

Physics Question on Heat Transfer

Two bodies AA and BB are placed in an evacuated vessel maintained at a temperature of 27C27^{\circ} C. The temperature of AA is 327C327^{\circ} C and that of BB is 227C227^{\circ} C. The ratio of heat loss from AA and BB is about

A

2:01

B

1:02

C

4:01

D

1:04

Answer

2:01

Explanation

Solution

For body A rate of heat loss is
EA=σA(60043004)E _{ A }=\sigma A \left(600^{4}-300^{4}\right)
For body BB rate of heat loss is
EB=σA(50043004)E_{B}=\sigma A\left(500^{4}-300^{4}\right)
So ratio of heat loss is
EA/EB=(60043004)/(50043004)E_{A} / E_{B}=\left(600^{4}-300^{4}\right) /\left(500^{4}-300^{4}\right)
=2.23:12:1=2.23: 1 \approx 2: 1