Question

Two blocks of masses 2 kg and 1 kg respectively are tied to the ends of a string which passes over a light frictionless pulley. The masses are held at rest at the same horizontal level and then released. The distance traversed by centre of mass in 2 s is –(g = 10 m/s²)

• A. 1.42 m
• B. 2.22 m
• C. 3.12 m
• D. 3.33 m

Answer 1

Answer: (B)

2.22 m

Answer 2

Here acceleration of system = 10/9 m/sec²

S_CM = $\frac{1}{2}$a_CMt² ̃ 2.22 m