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Physics Question on Mass Pulley System

Two blocks of mass m1 and m2 are connected at the both ends of a light string which is passing over a pulley. Radius of pulley is R and mass M, then find the acceleration of block.
light string

A

(m1−m2)(m1+m2+M2)\frac{(m_1 - m_2)}{(m_1 + m_2 + \frac{M}{2})}

B

m1gm1+m2\frac{m_1 g}{m_1 + m_2}

C

(m1+m2)gm1+m2\frac{(m_1 + m_2) g}{m_1 + m_2}

D

m2gm1+m2\frac{m_2 g}{m_1 + m_2}

Answer

(m1−m2)(m1+m2+M2)\frac{(m_1 - m_2)}{(m_1 + m_2 + \frac{M}{2})}

Explanation

Solution

The correct option is(A):(m1−m2)(m1+m2+M2)\frac{(m_1 - m_2)}{(m_1 + m_2 + \frac{M}{2})}