Question

Two blocks of mass 4 kg and 6 kg are placed in contact with each other on a frictionless horizontal surface. If we apply a push of 5 N on the heavier mass, the force on the lighter mass will be

$\xrightarrow { 5 N } 66 \mathrm {~kg}$

• A. 5 N
• B. 4 N
• C. 2 N
• D. None of the above

Answer 1

Answer: (C)

2 N

Answer 2

Let $m_{1} = 6kg,m_{2} = 4kg$ and $F = 5N$ (given)

Force on the lighter mass = $\frac{m_{2} \times F}{m_{1} + m_{2}} = \frac{4 \times 5}{6 + 4} = 2N$