Solveeit Logo

Question

Question: Two blocks are in contact on a frictionless table one has a mass m and the other 2 m as shown in fig...

Two blocks are in contact on a frictionless table one has a mass m and the other 2 m as shown in figure. Force F is applied on mass 2m then system moves towards right. Now the same force F is applied on m. The ratio of force of contact between the two blocks will be in the two cases respectively.

A

1 : 1

B

1 : 2

C

1 : 3

D

1 : 4

Answer

1 : 2

Explanation

Solution

When the force is applied on mass 2m contact force f1=mm+2mg=g3f _ { 1 } = \frac { m } { m + 2 m } g = \frac { g } { 3 }

When the force is applied on mass m contact force f2=2mm+2mg=23gf _ { 2 } = \frac { 2 m } { m + 2 m } g = \frac { 2 } { 3 } g

Ratio of contact forces f1f2=12\frac { f _ { 1 } } { f _ { 2 } } = \frac { 1 } { 2 }