Question

Two blocks are in contact on a frictionless table. One has mass $m$ and other 2 $m$ . A force $F$ is applied on 2 $m$ as shown in figure. Next the same force $F$ is applied from the right on $m$ . In the two cases respectively, the ratio of the force of contact between the two blocks will be

• A. 2:01
• B. 1:03
• C. 1:02
• D. 3:01

Answer 1

Answer: (C)

1:02

Answer 2

When force $F$ is applied on 2 $m$ from left, contact force, $F_{1}=\frac{m}{m + 2 m}F=\frac{F}{3}$ When force $F$ is applied on $m$ from right, contact force $F_{2}=\frac{2 m}{m + 2 m}F=\frac{2 F}{3}$ $?$ $F_{1}:F_{2}=1:2$