Question

Two blocks $A$ and $B$ of masses $m_A = 1 \; kg$ and $m_B = 3 \; kg$ are kept on the table as shown in figure. The coefficient of friction between $A$ and $B$ is $0.2$ and between $B$ and the surface of the table is also $0.2.$ The maximum force $F$ that can be applied on $B$ horizontally, so that the block $A$ does not slide over the block $B$ is : (Take $g = 10 \; m/s^2$)

• A. 16 N
• B. 40 N
• C. 12 /n
• D. 8 N

Answer 1

Answer: (A)

16 N

Answer 2

$F - 8 = 4 \times 2$ $F = 16\, N$