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Question: Two blocks 'A' and 'B' each of mass 'm' are placed on a smooth horizontal surface. Two horizontal fo...

Two blocks 'A' and 'B' each of mass 'm' are placed on a smooth horizontal surface. Two horizontal force F and 2F are applied on the 2 blocks 'A' and 'B' respectively as shown in figure. The block A does not slide on block B. Then the normal reaction acting between the two blocks is –

A

F

B

F2\frac{F}{2}

C

F3\frac{F}{\sqrt{3}}

D

3F

Answer

3F

Explanation

Solution

Acceleration of two mass system is a = F2m\frac{F}{2m} leftward

FBD of block A

N cos 600 – F = ma = mF2m\frac{mF}{2m} solving N = 3F