Solveeit Logo
Login

Question

Question: Two billiard balls A and B, each of mass 50 g and moving in opposite directions with speed of \(5ms^...

Two billiard balls A and B, each of mass 50 g and moving in opposite directions with speed of 5ms−15ms^{- 1}each, collide and rebound with the same speed. The impulse imparted to each ball is :

A

0.25kgms−10.25kgms^{- 1}

B

0.5kgms−10.5kgms^{- 1}

C

0.1kgms−10.1kgms^{- 1}

D

0.125kgms−10.125kgms^{- 1}

Answer

0.5kgms−10.5kgms^{- 1}

Explanation

Solution

Initial momentum of ball)A=(0.05kg)(5ms−1)=0.25ms−1A = (0.05kg)(5ms^{- 1}) = 0.25ms^{- 1}

As the speed is reversed on collision

Final momentum of the ballA=(0.05kg)(−5ms−1)=−0.25kgms−1A = (0.05kg)( - 5ms^{- 1}) = - 0.25kgms^{- 1}

Impulse imparted to the ball A

= Change in momentum of ball A

= −0.25kgms−1−0.25kgms−1=−0.5kgms−1- 0.25kgms^{- 1} - 0.25kgms^{- 1} = - 0.5kgms^{- 1}

Similarly,

Initial momentum of ball B =(0.05kg)(−5ms−1)=−0.25kgms−1(0.05kg)( - 5ms^{- 1}) = - 0.25kgms^{- 1}

Final momentum of ball B =(0.05kg)(5ms−1)=0.25ms−1(0.05kg)(5ms^{- 1}) = 0.25ms^{- 1}

Impulse imparted to the ball B =(0.25kgms−1)−(−0.25kgms−1)=0.5kgms−1(0.25kgms^{- 1}) - ( - 0.25kgms^{- 1}) = 0.5kgms^{- 1}

Impulse imparted to each ball is 0.5kgms−10.5kgms^{- 1} in

magnitude. The two impulses are opposite in direction