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Question

Physics Question on Current electricity

Two batteries, one of emf 18 volts and internal resistance 2Ω2\, \Omega and the other of emf 12 volts and internal resistance 1Ω1\, \Omega are connected as shown. The voltmeter V will record a reading of

A

30 volt

B

18 volt

C

15 volt

D

14 volt

Answer

14 volt

Explanation

Solution

From Kirchhoff's law.
I×2+I×1=1812I \times 2 + I \times 1 = 18 -12
Current in the circuit,

I=VR=63=2A\, \, \, \, I=\frac{V}{R}=\frac{6}{3}=2 \, A
Voltage drop across 2Ω,2\, \Omega,
V1=2×2=4V\, \, \, \, V_1 = 2 \times 2 = 4\, V
Voltmeter reading =184=14V.= 18 - 4 = 14\, V.