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Question: Two batteries of emf\(\varepsilon_{1}\) and\(\varepsilon_{2}\left( \varepsilon_{2} > \varepsilon_{1}...

Two batteries of emfε1\varepsilon_{1} andε2(ε2>ε1)\varepsilon_{2}\left( \varepsilon_{2} > \varepsilon_{1} \right) and internal resistances r1r_{1} and r2r_{2} respectively are connected in parallel as shown in figure.

A

The equivalent emf εeq\varepsilon_{eq} of the two cells is between and ε1\varepsilon_{1} and ε2,\varepsilon_{2}, i.e.ε1<εeq<ε2\varepsilon_{1} < \varepsilon_{eq} < \varepsilon_{2} .

B

The equivalent emf εeq\varepsilon_{eq} is smaller than ε1.\varepsilon_{1}.

C

The εeq\varepsilon_{eq} is given by εeq\varepsilon_{eq}= ε1+ε2\varepsilon_{1} + \varepsilon_{2}always.

D

εeq\varepsilon_{eq}is independent of internal resistances r1r_{1} and r2r_{2}

Answer

The equivalent emf εeq\varepsilon_{eq} of the two cells is between and ε1\varepsilon_{1} and ε2,\varepsilon_{2}, i.e.ε1<εeq<ε2\varepsilon_{1} < \varepsilon_{eq} < \varepsilon_{2} .