Question

Two base balls(masses; m1=100g, and m2=50g) are thrown. Both move with uniform velocity, but the velocity of m2 is 1.5 times that of m1.The ration of de Broglie wavelengths λ(m1) : λ(m2) is given by

• A. 4:3
• B. 3:4
• C. 2:1
• D. 1:2

Answer 1

Answer: (B)

3:4

Answer 2

Given :
m1 = 100 g
V1 = V1 m/s
m2 = 50 g
V2 = 1.5 V1 m/s
Now, Using the formula of de-Broglie's wavelength, we will get
$\lambda=\frac{h}{mv}$
$⇒\frac{λ_1}{λ_2}=\frac{m_2V_2}{m_1V_1}=\frac{50\times1.5V_1}{100V_1}=\frac{3}{4}$
So, the correct option is (B) : 3 : 4