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Question

Physics Question on Thermal Expansion

Two bars ot copper having same length but unequal diameter are heated to the same temperature. The change in length will be

A

more in thinner bar

B

more in thicker bar

C

same for both the bars

D

determined by the ratio of length and diameter of the bars

Answer

same for both the bars

Explanation

Solution

Δl=lαΔθ\Delta l=l \alpha \Delta \theta Δθ=\Delta \theta= change in temperature Δθ=\Delta \theta= same for both bars Δl=\therefore \Delta l= same α=\alpha= same h\stackrel{h}{\rightarrow} Iemperature coefficient Δl\Delta l does not depend on l=l= same length thickness of the rods Δl=\therefore \Delta l= same also Al will be same