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Question

Physics Question on Current electricity

Two bars of radius r and 2rare kept in contact as shown. An electric current I is passed through the bars. Which one of following is correct ?

A

Heat produced in bar BC is 4 times the heat produced in bar AB

B

Electric field in both halves is equal

C

Current density across AB is double that of across BC

D

Potential difference across AB is 4 times that of across BC

Answer

Heat produced in bar BC is 4 times the heat produced in bar AB

Explanation

Solution

Current flowing through both the bars is equal.
Now, the heat produced is given by
H=I2RtorH?RorHABHBC=RABRBCH = I^2 Rt \, or H ? R \, or \frac{H_{AB}}{H_{BC}}= \frac{R_{AB}}{R_{BC}}
=(1/2r)2(1/r)2(asR?1A?1r2)= \frac{(1/2r)^2}{(1/r)^2} \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \big( as \, R ? \frac{1}{A} ? \frac{1}{r^2}\big)
=14orHBC=4HAB= \frac{1}{4} \, or \, H_{BC} = 4H_{AB}